A car, starting off and moving uniformly accelerated, travels 5 meters in 1 second of movement.

A car, starting off and moving uniformly accelerated, travels 5 meters in 1 second of movement. How much distance will it cover in the second, third and fourth seconds?

S = V0 * t + a * t² / 2, S is the distance covered by the car (S = 5 m), V0 is the initial speed (V0 = 0 m / s, since the car started moving), and is the acceleration, t is movement time (t = 1 s).
S = a * t² / 2.
a = 2S / t² = 2 * 5 / 1² = 10 m / s².
a = const, since the car is moving uniformly.
S (2 s) = 10 * 2² / 2 – 5 = 20 – 5 = 15 m.
S (3 s) = 10 * 3² / 2 – 20 = 45 – 20 = 25 m.
S (4 s) = 10 * 4² / 2 – 45 = 80 – 45 = 35 m.
S1: S2: S3: S4 = 5: 15: 25: 35 = 1: 3: 5: 7.