# A car, the mass of which is m = 1200 kg, moves with an acceleration a = 1.04 m / s ^. coefficient

September 30, 2021 | education

| **A car, the mass of which is m = 1200 kg, moves with an acceleration a = 1.04 m / s ^. coefficient of friction q = 0.2 find the traction force of the car**

m = 1200 kg.

g = 9.8 m / s2.

a = 1.04 m / s2.

μ = 0.2.

F -?

Let us write 2 Newton’s laws: Frav = m * a, where Frav is the resultant of all forces that act on the body, m is the mass of the body, and is the acceleration of the body’s motion.

We find the resultant of all forces by the formula: Frav = F + Ftr + m * g + N.

OH: m * a = F – Ftr.

OU: 0 = m * g – N.

F = m * a + Ftr.

m * g = N.

Ftr = μ * N = μ * m * g.

F = m * a + μ * m * g.

F = 1200 kg * 1.04 m / s2 + 0.2 * 1200 kg * 9.8 m / s2 = 3600 N.

Answer: the car develops a traction force F = 3600 N.

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