A car, the mass of which is m = 1200 kg, moves with an acceleration a = 1.04 m / s ^. coefficient
| September 30, 2021 | education
A car, the mass of which is m = 1200 kg, moves with an acceleration a = 1.04 m / s ^. coefficient of friction q = 0.2 find the traction force of the car
m = 1200 kg.
g = 9.8 m / s2.
a = 1.04 m / s2.
μ = 0.2.
F -?
Let us write 2 Newton’s laws: Frav = m * a, where Frav is the resultant of all forces that act on the body, m is the mass of the body, and is the acceleration of the body’s motion.
We find the resultant of all forces by the formula: Frav = F + Ftr + m * g + N.
OH: m * a = F – Ftr.
OU: 0 = m * g – N.
F = m * a + Ftr.
m * g = N.
Ftr = μ * N = μ * m * g.
F = m * a + μ * m * g.
F = 1200 kg * 1.04 m / s2 + 0.2 * 1200 kg * 9.8 m / s2 = 3600 N.
Answer: the car develops a traction force F = 3600 N.
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