A car traveling at a speed of 36 km / h moves with an average acceleration of 0.2 m / s ^ 2.

A car traveling at a speed of 36 km / h moves with an average acceleration of 0.2 m / s ^ 2. how far the car will go in 10 seconds from the start of the countdown. Find the car’s instantaneous speed at the end of 10 seconds.

A car traveling at a speed of 36 km / h which moves with an average acceleration of 0.2 m / s ². We need to find the path that the car will travel in 10 seconds from the start of the countdown and find the instantaneous speed of the car at the end of 10 seconds.

In order to solve the problem, we need to memorize some formulas of mechanics.

Distance traveled by car:
S = V 0 * t + a * t ² / 2,

where V 0 is the initial speed of the car, a is the acceleration of the car and t is the time of movement of the car.

Given V 0 = 36 km / h = 36 * 1000/3600 = 10 m / s, t = 10 s and a = 0.2 m / s ².
Distance covered by the car in tenth second:

S = 10 * 10 + 0.2 * (10) ² / 2 = 100 + 10 = 110 m.

Now, find the instantaneous vehicle speed at the end of 10 seconds using the following formula:

V = V 0 + a * t;

V = 10 +0.2 * 10 = 10 + 2 = 12 m / s.

Answer: S = 110 m and V = 12 m / s.