A car weighing 1.8 tons starts moving along a horizontal road with a constant acceleration a = 2.5.

A car weighing 1.8 tons starts moving along a horizontal road with a constant acceleration a = 2.5. Neglecting the resistance forces, determine the instantaneous power of the engine thrust force after a time interval t = 4.0 s from the start of movement.

To determine the value of the instantaneous power of the presented car, we will use the formula: N = F * V = (m * a) * (a * t) = m * a ^ 2 * t.

Variables: m is the mass of the presented car (m = 1.8 t = 1.8 * 10 ^ 3 kg); a – constant acceleration (a = 2.5 m / s2); t – acceleration time (t = 4 s).

Let’s perform the calculation: N = m * a ^ 2 * t = 1.8 * 103 * 2.5 ^ 2 * 4 = 45 * 10 ^ 3 W.

Answer: The instantaneous power of the presented vehicle after 4 seconds was 45 kW.