A car weighing 10 tons, moves at a speed of 0.5 m / s, stops under the action of a friction
| February 27, 2021 | education
A car weighing 10 tons, moves at a speed of 0.5 m / s, stops under the action of a friction force of 1000 N. How long did the braking last?
Given: m (the mass of a given carriage) = 10 t (in the SI system m = 10 * 103 kg); V (initial speed of the car) = 0.5 m / s; Ffr (effective frictional force) = 1000 N.
The duration of braking of a given car can be expressed from the equality: F * t = ΔP = m * V, whence t = m * V / F.
Let’s make a calculation: t = 10 * 10 ^ 3 * 0.5 / 1000 = 5 s.
Answer: Braking of a given carriage lasted 5 seconds.
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