A car weighing 1020 kg stops when braking for 5 seconds, while passing a distance of 25 m

A car weighing 1020 kg stops when braking for 5 seconds, while passing a distance of 25 m equally slowly. Find the initial vehicle speed and braking force.

Initial data: m (vehicle weight) = 1020 kg; t (deceleration duration) = 5 s; S (distance traveled) = 25 m; V (final speed) = 0 m / s.

1) Determine the vehicle acceleration and initial speed:

V = V0 + a * t; V0 = -a * t = -5a.

S = (V ^ 2 – V0 ^ 2) / 2a = -25a ^ 2 / 2a = -12.5a.

a = -S / 12.5 = 25 / 12.5 = -2 m / s ^ 2.

V0 = -5 * (-2) = 10 m / s.

2) Braking force: Fsopr. = | m * a | = 1020 * 2 = 2040 N.

Answer: The initial speed of the vehicle is 10 m / s and the braking force is 2040 N.