A car weighing 1500kg begins to move horizontally with an acceleration of 0.5 / s squared.

A car weighing 1500kg begins to move horizontally with an acceleration of 0.5 / s squared. Movement resistance 500 N. Determine the thrust force developed by the engine.

m = 1500 kg.
g = 10 m / s2.
a = 0.5 m / s2.
Fcopr = 500 N.
Fт -?
For the movement of a car, we write 2 Newton’s law in vector form: m * a = Fт + m * g + N + Fcopr, where Ft is the engine thrust force, m * g is the gravity force, N is the reaction force of the road surface, Fcopr is the resistance force …
ОХ: m * a = Fт – Fcopr, since the resistance force Fcopr is always directed in the opposite direction of the vehicle movement.
OU: 0 = – m * g + N.
Let us express the traction force of the car: Ft = m * a + Fcopr.
Ft = 1500 kg * 0.5 m / s2 + 500 N = 1250 N.
Answer: when driving, the traction force of the car is Ft = 1250 N.