A car weighing 2 tons moves evenly along a horizontal highway.
| February 10, 2021 | education
A car weighing 2 tons moves evenly along a horizontal highway. determine the traction force of the car if the drag coefficient is 0.02. disregard air resistance.
m = 2 t = 2000 kg.
g = 10 m / s2.
μ = 0.02.
Fт -?
According to Newton’s 1 law, a body moves uniformly in a straight line if no forces act on it or the actions of forces are compensated.
In vector form: Ft + m * g + N + Ftr = 0.
For projections on the horizontal and vertical axes, Newton’s law will look like:
ОХ: Ft – Ftr = 0.
OU: – m * g + N = 0.
Ft = Ftr.
N = m * g.
The friction force Ffr is determined by the formula: Ffr = μ * N = μ * m * g.
Fт = μ * m * g.
Ft = 0.02 * 2000 kg * 10 m / s2 = 400 N.
Answer: the thrust force of the engine is Ft = 400 N.
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