A car weighing 20 tons, moving at a speed of 0.3 m / s, overtakes a car weighing 30 tons, moving at a speed of 0.2 m / s.

| March 25, 2021 | education

A car weighing 20 tons, moving at a speed of 0.3 m / s, overtakes a car weighing 30 tons, moving at a speed of 0.2 m / s. What is the speed of the cars after interaction if the impact is not elastic?

Since the impact is considered inelastic, the cars move further together and according to the law of conservation of momentum:

m1V1 + m2V2 = (m1 + m2) * U1.2, where m1 is the mass of the first car (m1 = 20 t = 20,000 kg), V1 is the speed of the first car (V1 = 0.3 m / s), m2 is the mass of the second of the car (m2 = 30 t = 30,000 kg), V2 is the speed of the second car (V2 = 0.2 m / s), U1.2 is the speed of the cars after interaction.

U1.2 = (m1V1 + m2V2) / (m1 + m2) = (20,000 * 0.3 + 30,000 * 0.2) / (20,000 + 30,000) = 12,000 / 50,000 = 0.24 m / s.



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