A car weighing 3 tons is moving at a speed of 28.8 km / h. when braking, stops in 6 seconds. Find the braking force.

According to Newton’s second law:

F = m * a, where F is the required braking force (N), m is the mass of the car (m = 3 t = 3000 kg), and is the acceleration of the car (m / s²).

Vehicle acceleration:

a = (V – V0) / t, where V is the final speed (V = 0 m / s), V0 is the initial speed (V0 = 28.8 km / h = 28.8 * 1000/3600 = 8 m / s ), t is the braking time of the vehicle (t = 6 s).

Let’s calculate the braking force:

F = m * (V – V0) / t = 3000 * (0 – 8) / 6 = 4000 N = 4 kN.

Answer: The braking force is 4 kN.



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