A car weighing 3 tons is moving at a speed of 72 km / h. Calculate the braking distance of the vehicle

| August 18, 2021 | education

A car weighing 3 tons is moving at a speed of 72 km / h. Calculate the braking distance of the vehicle if the braking force is 2500 N.

m = 3 t = 3000 kg.

V0 = 72 km / h = 20 m / s.

V = 0 m / s.

Ftor = 2500 N.

S -?

Since a constant force Ftor acts during braking, the car will move with uniform acceleration. With uniformly accelerated motion, the path S traversed by him is expressed by the formula: S = V0 * t – a * t ^ 2/2.

The acceleration of the car a will be expressed by the formula: a = Ftor / m.

a = 2500 N / 3000 kg = 0.83 m / s2.

The time of movement until a complete stop t is expressed by the formula: t = (V0 – V) / a = (V0 – V) * m / Ftor = V0 * m / Ftor.

t = 20 m / s * 2500 N / 3000 kg = 16.7 s.

S = 20 m / s * 16.7 s – 0.83 m / s2 * (16.7 s) 2/2 = 218.3 m.

Answer: the braking distance of the car was S = 218.3 m.



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