A car weighing 4 * 10 ^ 3 kg moves along a horizontal section of the road. at a speed of 20 m / s, the engine is turned off.
| June 15, 2021 | education
A car weighing 4 * 10 ^ 3 kg moves along a horizontal section of the road. at a speed of 20 m / s, the engine is turned off. What work does the friction force do until the car comes to a complete stop?
To calculate the value of the work of the friction force performed when braking the presented car, we use the formula: A = ΔEk = ma * Vn ^ 2/2.
Values of variables: ma – vehicle weight (ma = 4 * 10 ^ 3 kg); Vн – speed before engine shutdown (Vн = 20 m / s).
Let’s make a calculation: A = ma * Vn ^ 2/2 = 4 * 10 ^ 3 * 20 ^ 2/2 = 800 * 10 ^ 3 J.
Answer: The friction force, according to the calculation, performed the work of 800 kJ.
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