A car weighing 50 tons stands on the rails. What force must be applied to move the car from
| March 28, 2021 | education
A car weighing 50 tons stands on the rails. What force must be applied to move the car from its place if the coefficient of friction is 0.05.
According to Newton’s second law:
ma = F – Ftr, therefore, to move the car from the place F> Ftr.
Friction force: Ftr is the sliding friction force (Ftr. = Μ * N, where μ is the friction coefficient (μ = 0.05), N is the support reaction force (N = Ft = m * g, where m is the mass of the car (m = 50 t = 50,000 kg), g is the acceleration of gravity (let us assume g = 10 m / s²)).
Ftr = μ * m * g = 0.05 * 50,000 * 10 = 25,000 N = 25 kN.
Answer: To move the car from its place, it is necessary to apply a force of more than 25 kN.
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