A car with a mass of 1 t moves along a horizontal road with an acceleration of 0.5 m, s ^ 2.

A car with a mass of 1 t moves along a horizontal road with an acceleration of 0.5 m, s ^ 2. Determine the traction force developed by the engine if the coefficient of friction when the vehicle is moving is 0.1.

m = 1 t = 1000 kg.

g = 10 m / s2.

a = 0.5 m / s2.

μ = 0.1.

Fт -?

When the car is moving, its traction force Ft is used to overcome the friction force Ftr and impart acceleration a to the car. 2 Newton’s law will have the form: m * a = Ft – Ftr.

Ft = Ftr + m * a.

With horizontal movement, the friction force Ftr, which acts on the car, is determined by the formula: Ftr = μ * m * g, where μ is the coefficient of friction of the wheels on the road.

The traction force of the car Ft will be determined by the formula: Ft = μ * m * g + m * a = m * (μ * g + a).

Ft = 1000 kg * (0.1 * 10 m / s2 + 0.5 m / s2) = 1500 N.

Answer: when driving, the car engine develops a traction force Ft = 1500 N.