A car with a mass of 10 tons, moving at a speed of 0.3 m / s, overtakes a car with a mass of 20 tons

| June 20, 2021 | education

A car with a mass of 10 tons, moving at a speed of 0.3 m / s, overtakes a car with a mass of 20 tons, moving at a speed of 0.1 m / s. What is the speed of the carriages after interaction, if they subsequently move together.

Given: the first car under consideration (m1 = 10 t = 10 * 10 ^ 3 kg; V1 = 0.3 m / s); the second considered car (m2 = 20 t = 20 * 10 ^ 3 kg; V2 = 0.1 m / s); inelastic impact (cars after interaction move together).

The speed of the cars under consideration after interaction is determined by the formula (we use the law of conservation of momentum): V = (V1 * m1 + V2 * m2) / (m1 + m2).

Calculation: V = (0.3 * 10 * 10 ^ 3 + 0.1 * 20 * 10 ^ 3) / (10 * 10 ^ 3 + 20 * 10 ^ 3) = 0.167 m / s.

Answer: The cars will move at a speed of 0.167 m / s.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.