A car with a mass of 1000 kg moves evenly along a straight section of the highway. Its engine develops

A car with a mass of 1000 kg moves evenly along a straight section of the highway. Its engine develops a traction force of 0.6 Kn. Draw all the forces acting on the car. Find the resultant of these forces.

m = 1000 kilograms – vehicle weight;

F = 0.6 kN – traction force developed by the car engine.

It is required to determine F (Newton) – the resultant of all forces acting on the car.

The following forces act on the car:

Vertically:

The downward force of gravity and the upward reaction force of the support counterbalance each other (the resultant is zero).

Horizontally:

The vehicle’s traction force along the motion, the frictional force directed against the motion, and the air resistance force directed against the motion.

Since, according to the condition of the problem, the car moves uniformly, that is, with a constant speed, it means that the resultant of all forces horizontally is also equal to zero.

Answer: the resultant of the forces acting on the car is zero.