A car with a mass of 14 tons, moving away from a place, passes the first 50 m in 10 seconds.

Given: m (mass of a given vehicle) = 14 t (in SI m = 14 * 10 ^ 3 kg); movement from a place; S (distance traveled) = 50 m; t (duration of movement) = 10 s; μ (drag coefficient) = 0.05.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

The traction force acting on a given vehicle can be expressed from the following equality: m * a = Ft – Fc and Ft = m * a + Fc = m * (2S / t2) + μ * N = m * (2S / t2) + μ * m * g.

Calculation: Ft = 14 * 10 ^ 3 * (2 * 50/10 ^ 2) + 0.05 * 14 * 10 ^ 3 * 10 = 21 * 10 ^ 3 N (21 kN).