A car with a mass of 1500 kg, moving at a speed of 80 km / h, stops under the influence of the braking force F
A car with a mass of 1500 kg, moving at a speed of 80 km / h, stops under the influence of the braking force F during time t, while traveling at the same time a distance of 50 m. find unknown quantities.
m = 1500 kg.
V0 = 80 km / h = 22.22 m / s.
V = 0 m / s.
S = 50 m.
Ftorm -?
t -?
When braking, the braking force Fstorm is found according to 2 Newton’s laws: Fstorm = m * a.
We express the acceleration of the car by the formula: a = (V0 ^ 2 -V ^ 2) / 2 * S.
Since V = 0 m / s, then a = V0 ^ 2/2 * S.
Ftorm = m * V0 ^ 2/2 * S.
Ftorm = 1500 kg * (22.22 m / s) ^ 2/2 * 50 m = 7406 N.
Let us write down the definition for the acceleration of the body: a = (V0 – V) / t.
Since V = 0 m / s, then a = V0 / t.
t = V0 / a = V0 * 2 * S / V0 ^ 2 = 2 * S / V0.
t = 2 * 50 m / 22.22 m / s = 4.5 s.
Answer: Ftorm = 7406 N, t = 4.5 s.