A car with a mass of 16 tons, moving away, develops an acceleration of 2 m / second squared

| May 31, 2021 | education

A car with a mass of 16 tons, moving away, develops an acceleration of 2 m / second squared, determine the engine thrust if the coefficient of resistance to movement is 0.02.

To calculate the thrust force of the engine of the presented car, consider the equality: m * a = F = Ftyag – Ftr = Ftyag – μ * m * g, whence we express: Ftyag = m * a + μ * m * g = (a + μ * g) * m.

Const: q – acceleration due to gravity (approx. Q ≈ 10 m / s2).

Data: a – acceleration achieved by the represented vehicle (a = 2 m / s2); μ – coefficient. resistance (μ = 0.02); m is the mass of the presented car (m = 16 t = 16 * 10 ^ 3 kg).

Calculation: Ftyag = (a + μ * g) * m = (2 + 0.02 * 10) * 16 * 10 ^ 3 = 35.2 * 10 ^ 3 N.

Answer: The thrust force of the engine, according to the calculation, is 35.2 kN.



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