A car with a mass of 1800 kg, moving from a state of rest along a horizontal path, in 10 seconds

A car with a mass of 1800 kg, moving from a state of rest along a horizontal path, in 10 seconds from the start of movement reaches a speed of 30 m / s. It is necessary to determine the thrust force of the engine

Task data: m (weight of the taken vehicle) = 1800 kg; rectilinear movement from a state of rest; t (time elapsed from the start of movement) = 10 s; V1 (reached speed) = 30 m / s.

The traction force of the engine of the taken car is determined using the formula for calculating the impulse of force: F * t = m * V1 – m * V0 = m * V1 – 0, whence F = m * V1 / t.

Let’s perform the calculation: F = 1800 * 30/10 = 5.4 * 10 ^ 3 N or 5.4 kN.

Answer: The vehicle taken has an engine thrust force of 5.4 kN.