A car with a mass of 2 t moves from a standstill with an acceleration of 0.6 m / s².

A car with a mass of 2 t moves from a standstill with an acceleration of 0.6 m / s². What thrust does the engine develop during this movement if the coefficient of friction is 0.04?

According to Newton’s second law:

ma = F – Ftr, where m is the mass of the car (m = 2 t = 2000 kg), a is the acceleration (a = 0.6 m / s²), F is the thrust force of the car engine, Ftr is the sliding friction force (Ftr. = μ * N, where μ is the coefficient of friction (μ = 0.04), N is the reaction force of the support (N = Fт (gravity) = m * g, where g is the acceleration of gravity (let us take g = 10 m / s² ))).

F = ma + Ftr = ma + μ * m * g = 2000 * 0.6 + 0.04 * 2000 * 10 = 2000 N = 2 kN.

Answer: The thrust force of the car engine is 2 kN.