A car with a mass of 20 tons, moving at a speed of 3 m / s on a horizontal section, is expensive
A car with a mass of 20 tons, moving at a speed of 3 m / s on a horizontal section, is expensive, collides and clings to a fixed platform weighing 15 tons. Determine the speed of the joint movement of the carriage and the platform after the impact.
Given:
m1 = 20,000 tons is the mass of a moving car;
v1 = 3 m / s (meters per second) – the speed at which the carriage is moving;
m2 = 15 tons = 15000 – fixed platform mass.
It is required to determine v (m / s) – the speed of the joint movement of the car and the platform after the impact.
Since the condition of the problem is not specified, we assume that the adhesion occurred as a result of an absolutely inelastic impact.
Then, given that the platform speed was zero (v2 = 0), we get:
m1 * v1 + m2 * v2 = (m1 + m2) * v;
m1 * v1 = (m1 + m2) * v;
v = m1 * v1 / (m1 + m2) = 20,000 * 3 / (20,000 + 15,000) = 60,000/35,000 = 60/35 = 1.7 m / s (the result has been rounded to one decimal place).
Answer: the speed of the joint movement of the car and the platform after the impact will be equal to 1.7 m / s.