A car with a width of d = 2.4 m, moving at a speed of V = 15 m / s, was pierced by a bullet flying perpendicular

A car with a width of d = 2.4 m, moving at a speed of V = 15 m / s, was pierced by a bullet flying perpendicular to the movement of the car. The displacement of the holes in the walls of the car relative to each other is 6 cm. What is the speed of the bullet.

d = 2.4 m.

V = 15 m / s.

a = 6 cm = 0.06 m.

Vп -?

The bullet flies perpendicular to the movement of the car, breaks through one wall of the car and, while it reaches the second wall, the car has time to travel the distance a.

Let us express the distance a that the car has traveled during the time the bullet moves in the car t by the formula: a = V * t.

t = a / V.

In the car, the bullet in time t was able to fly from one wall to the second a distance equal to the width of the car d. We will express the speed of the bullet inside the car Vp by the formula: Vp = d / t.

The bullet velocity Vp will be determined by the formula: Vp = d * V / a.

Vp = 2.4 m * 15 m / s / 0.06 m = 600 m / s.

Answer: the speed of a bullet inside the car is Vp = 600 m / s.