A cargo of humanitarian aid was dropped from an airplane flying at a speed of 500 km / h from a height

A cargo of humanitarian aid was dropped from an airplane flying at a speed of 500 km / h from a height of 300 meters. How far from the drop point should the cargo be met?

These tasks: Vg (horizontal speed of humanitarian aid cargo, aircraft) = 500 km / h = 138.89 m / s; h (initial height of cargo, aircraft) = 300 m.

Constants: g (acceleration due to gravity) = 9.81 m / s2.

1) The duration of the fall of the humanitarian aid cargo: h = g * t ^ 2/2, whence we express: t = √ (2h / g) = √ (2 * 300 / 9.81) = 7.82 s.

2) Distance from the drop point to the meeting point: S = Vg * t = 138.89 * 7.82 = 1086 m.

Answer: A cargo of humanitarian aid should be met at a distance of 1086 m from the drop point.