A cargo was dropped from a helicopter located at an altitude of 180 m. if the helicopter

A cargo was dropped from a helicopter located at an altitude of 180 m. if the helicopter is stationary, will the cargo reach the ground in time?

Initial data: h (the height at which the helicopter is located, the path covered by the cargo) = 180 m; the helicopter is stationary; V0 (initial speed of the load) = 0 m / s.

Reference values: according to the condition a (acceleration of the load) = g (acceleration of gravity) = 9.8 m / s2.

We express the duration of the drop of the load from the formula: S = h = g * t ^ 2/2, whence t = √ (2h / g).

Calculation: t = √ (2 * 180 / 9.8) = 6.06 s.

Answer: The cargo will reach the ground in 6.06 s.