A cart weighing 200 grams moves under the action of a horizontal force vector with an acceleration of 2 m / s2.

A cart weighing 200 grams moves under the action of a horizontal force vector with an acceleration of 2 m / s2. What is the mass of the load placed on the trolley if the acceleration under the same force is 0.4 m / s2

Given:
m1 = 200g 0.2kg
a1 = 2 m / s ^ 2
a2 = 0.4 m / s ^ 2
m2-?
Decision:
F = ma
The condition says that under the action of the same force, therefore, F1 = F2
F1 = m1 * a1
F1 = 0.2 * 2 = 0.4 (H)
F1 = F2 = 0.4 (H)
F2 = a2 * m2
m2 = a2 / F2
m2 = 0.4 / 0.4 =
1 kg)
Answer: m2 = 1kg