A cast iron ball weighing 14 kg was dipped into kerosene. Determine its weight in liquid?

Given:

m = 14 kilograms – the mass of the cast iron ball;

g = 10 m / s ^ 2 – acceleration of gravity;

ro = 7000 kg / m ^ 3 – density of cast iron;

ro1 = 800 kg / m ^ 3 is the density of kerosene.

It is required to determine the weight of the cast iron ball P (Newton) in the liquid.

The weight of the cast iron ball in air will be:

P1 = m * g = 14 * 10 = 140 Newton.

The Archimedean force acting on the ball will be equal to:

A = ro1 * V * g = ro1 * m * g / ro = 800 * 14 * 10/7000 = 16 Newtons.

Then the weight of the ball in the liquid will be equal to:

P = P1 – A = 140 – 16 = 124 Newtons.

Answer: the weight of the ball in kerosene will be equal to 124 Newtons.