A cast-iron boiler, weighing 2 kg, was poured 1.5 liters. water. What amount of heat will the boiler

A cast-iron boiler, weighing 2 kg, was poured 1.5 liters. water. What amount of heat will the boiler with water receive when the water is heated from 10 degrees to 60

Q = Q1 (cast iron boiler) + Q2 (water) = C1 * m1 * (t2 – t1) + C2 * m2 * (t2 – t1) = (C1 * m1 + C2 * m2) * (t2 – t1).

Calculation data: C1 – beats. heat capacity of cast iron (C1 = 540 J / (K * kg)), m1 is the mass of the boiler (m1 = 2 kg), C2 is beats. heat capacity of water (C2 = 4200 J / (K * kg)), m2 is the mass of water (a volume of 1.5 liters of water has a mass of 1.5 kg), t2 is the temperature of the boiler with water after heating (t2 = 60 ° C) , t1 is the temperature before heating (t1 = 10 ° С).

Payment:

Q = (540 * 2 + 4200 * 1.5) * (60 – 10) = 7380 * 50 = 369 kJ.