A cast iron part has a volume of 1.8 cm3. What volume will an aluminum part of the same mass have?

Given:

V1 = 1.8 cubic centimeters = 0.0018 m ^ 3 – the volume of the cast iron part;

ro1 = 7000 kg / m ^ 3 – density of cast iron;

ro2 = 2700 kg / m ^ 3 is the density of aluminum.

It is required to determine the volume of an aluminum part V2 (m ^ 3).

Let’s find the mass of the cast iron part:

m1 = ro1 * V1 = 7000 * 0.0018 = 12.6 kilograms.

From the condition of the problem, m1 = m2, then:

V2 = m2 / ro2 = m1 / ro2 = 12.6 / 2700 = 0.0047 m ^ 3 (4.7 cubic centimeters).

Answer: The volume of an aluminum part will be 4.7 cubic centimeters.