A cast iron weighing 5.1 kg has cooled from 220 degrees to 20 degrees.

A cast iron weighing 5.1 kg has cooled from 220 degrees to 20 degrees. How much heat is given to the surrounding bodies?

Given: m (weight of cast iron taken) = 5.1 kg; t1 (initial temperature of the iron) = 220 ºС; t2 (final temperature) = 20 ° C.

Reference values: Сч (specific heat capacity of cast iron) = 540 J / (kg * K).

The amount of heat given off by the cast iron taken to the surrounding bodies is determined by the formula: Q = Сч * m * (t1 – t2).

Calculation: Q = 540 * 5.1 * (220 – 20) = 550.8 * 10 ^ 3 J = 550.8 kJ.

Answer: The taken cast iron gave 550.8 kJ of heat to the surrounding bodies.