A certain body can accelerate to a speed 3000 times less than the speed of light.

A certain body can accelerate to a speed 3000 times less than the speed of light. What distance will it cover, moving in a straight line in 0.01 seconds?

The path traveled by the body can be calculated using the formula:
S = V * t, where S is the distance traveled (m), V is the speed of the body (V = C / 3000, where C is the speed of light propagation in vacuum (C = 300,000 km / s = 3 * 10 ^ 8 m / s)), t is the time of movement (t = 0.01 s).
Let’s calculate the distance traveled:
S = V * t = (C / 3000) * t = ((3 * 10 ^ 8) / 3000) * 0.01 = 1000 m = 1 km.
Answer: The body will travel a distance of 1 km.



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