A charge of 0.2 C passes through the filament of a light bulb from a flashlight in a time of 1 s.

A charge of 0.2 C passes through the filament of a light bulb from a flashlight in a time of 1 s. What is the current in the light bulb?

The current strength in the filament of the light bulb is calculated by the formula:
I = q / t, where q is the charge passed through the cross-section of the lamp filament (q = 0.2 C), t is the charge passage time (t = 1 s).
Let’s calculate the current in the filament of the light bulb:
I = q / t = 0.2 / 1 = 0.2 A.
Answer: The current in the filament of the bulb is 0.2 A (200 mA, 200,000 μA).