A charge of 300 C passed through a conductor with a resistance of 20 ohms in 5 minutes.

A charge of 300 C passed through a conductor with a resistance of 20 ohms in 5 minutes. Determine the work of the current during this time.

Given:

R = 20 Ohm – conductor resistance;

q = 300 Coulomb – the charge that passed through the conductor during the time interval t;

t = 5 minutes = 300 seconds – time span.

It is required to determine A (Joule) – the work of the amperage during this time.

Find the current in the conductor:

I = q / t = 300/300 = 1 Ampere ..

Then the voltage in the conductor will be equal to:

U = I * R = 1 * 20 = 20 Volts

The power of the electric current will be equal to:

W = U * I = 20 * 1 = 20 watts.

The work of the amperage will be equal to:

A = W * t = 20 * 300 = 6000 Joules.

Answer: in 5 minutes, the current will perform work equal to 6000 Joules.