A chord 16 cm long was drawn in a circle with a radius of 10 cm. What is the distance

A chord 16 cm long was drawn in a circle with a radius of 10 cm. What is the distance from the center of the circle to the given chord?

Let’s construct the diameter of the AD circle parallel to the BC chord and draw the radii of the OB and OS circle. Since ОВ = ВС = 10 cm, the BOC triangle is isosceles.
The height OH of an isosceles triangle is also its median, then BH = CH = BC / 2 = 16/2 = 8 cm.
The BOH triangle is rectangular, then OH ^ 2 = OB ^ 2 – BH ^ 2 = 100 – 64 = 36.
OH = 6 cm.
Answer: The distance from the center of the circle to the center of the chord is 6 cm.