A chord AC and a diameter AB are drawn through point a of the circle find the height of the triangle ABC

A chord AC and a diameter AB are drawn through point a of the circle. find the height of the triangle ABC, drawn from the vertex c, if the chord is 30cm and the diameter is 50cm.

Since the inscribed angle ACB is based on the diameter of the circle, this angle is 900, and therefore the triangle ABC is rectangular.

Define the leg CB of the right-angled triangle ABC AO by the Pythagorean theorem.

BC ^ 2 = AB ^ 2 – AC ^ 2 = 2500 – 900 = 1600.

BC = 40 cm.

Let’s define the area of a triangle using two formulas and equate their values.

Savs = (AC * BC) / 2 = 30 * 40/2 = 600 cm2.

Savs = (AB * CH) / 2 = 50 * CH / 2 = 25 * N.

Then: 25 * CH = 600.

CH = 600/25 = 24 cm.

Answer: The height of the triangle is 24 cm.