A chord BC = 8cm is drawn in the circle O. Find the distance from the center to the segment BC if the radius = 5cm.

The distance from the center of the circle to the BC chord will be the perpendicular OH, which will be the height of the BOC triangle.

The ВOС triangle is isosceles, since OB = OС = R = 5 cm.Then the OH height will also be the median of the ВOС triangle, and then ВH = CH = BC / 2 = 8/2 = 4 cm.

In the right-angled triangle BOН, we determine the length of the leg OH using the Pythagorean theorem.

OH ^ 2 = OB ^ 2 – BH ^ 2 = 5 ^ 2 – 4 ^ 2 = 25 – 16 = 9.

OH = 3 cm.

Answer: The distance from point O to the BC chord is 3 cm.



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