A chord of length 8 is drawn in a circle with a radius of 5. Find the distance from the center to the chord.
| February 12, 2021 | education
Let’s draw the diameter of the AВ circle parallel to the BC chord.
The radii of the circle OB and OC form an isosceles triangle DOC with the chord.
The height OH of an isosceles triangle is also its median, then BH = CH = BC / 2 = 8/2 = 4 cm.
The DOН triangle is rectangular, then OH ^ 2 = OB ^ 2 – BH ^ 2 = 25 – 16 = 9.
OH = 3 cm.
Answer: The distance from the center of the circle to the chord is 3 cm.
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