A circle is inscribed in a trapezoid with a median line of 5.6. Find the perimeter of the trapezoid.

Since the middle line of the trapezoid is equal to half the sum of the lengths of the bases of the trapezoid, then

AD + BC = 2 * KM = 2 * 5.6 = 11.2 cm.

A circle can be inscribed into a trapezoid if and only if the sum of the opposite sides of the trapezoid is equal to each other.

Then AD + BC = AB + CD = 11.2 cm.

The perimeter of the trapezoid will be:

Ravsd = (AD + BC) + (AB + CD) = 11.2 + 11.2 = 22.4 cm.

Answer: The perimeter of the trapezoid is 22.4 cm.

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