A circle is inscribed in an isosceles trapezoid. The perimeter of the trapezoid is 56 cm.
A circle is inscribed in an isosceles trapezoid. The perimeter of the trapezoid is 56 cm. The tangency point divides the lateral side into segments, one of which is 5 cm. Find the base of the trapezoid.
From the center O of the circle, draw the radii to the points of tangency of the circle and the sides of the trapezoid.
By condition, ВK = СР = 5 cm.
By the property of tangents drawn to a circle from one point, the lengths of these tangents are equal. Then ВK = ВM = CM = CP = 5 cm.
BC = BM + CM = 5 + 5 = 10 cm.
Also by the property of tangents, AK = AH = DР = DН.
Let AK = AH = AR = DН = X cm.
The perimeter of the trapezoid is: Ravsd = AK = AH = DR = DН + ВK + BC + СР = 20 + 4 * X.
4 * X = 56 – 20 = 36.
X = 36/4 = 9 cm.
Then AD = 2 * X = 18 cm.
Answer: The bases of the trapezoid are 10 cm and 18 cm.