A circle is inscribed in the ABCD quadrilateral, AB = 22, CD = 17. find the perimeter of the quadrilateral ABCD.

If a circle is inscribed in a quadrilateral, then the sum of the two opposite sides will be equal to the sum of the other two opposite sides.

AB + СD = 22 + 17 = 39

This means that the sum of BC +AD is also 39.

Then the perimeter of the quadrilateral is:

(AB + СD) + (BC + AD) = 39 + 39 = 78

Answer: The perimeter is 78.



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