A circle is inscribed into the trapezoid, the sum of the lengths of the sides of which is 28, find the perimeter of the trapezoid.

Since a circle is inscribed in the trapezoid ABCD, the sum of the lengths of the bases of this trapezoid is equal to the sum of the lengths of its lateral sides.

(AB + CD) = (BC + AD) = 28 cm.

Then the perimeter of the trapezoid will be equal to: Ravsd = (AB + CD) + (BC + AD) = 28 + 28 = 56 cm.

Answer: The perimeter of the trapezoid is 56 cm.



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