A circus performer weighing 60 kg falls into a stretched net from a height of 4m.

A circus performer weighing 60 kg falls into a stretched net from a height of 4m. With what force does the net act on the artist if it deflects at the same time by 1m?

To determine the value of the force acting on the circus artist from the side of the net, we use the equality: m * g * (h + x) = k * x2 / 2 = Fupr * x / 2, whence we express: Fupr = 2 * m * g * ( h + x) / x.

Constants and variables: m (mass of the circus artist) = 60 kg; g – acceleration due to gravity (g ≈ 10 m / s2); h is the artist’s height above the net (h = 4 m); x – mesh deflection (x = 1 m).

Let’s perform the calculation: Fcont = 2 * m * g * (h + x) / x = 2 * 60 * 10 * (4 + 1) / 1 = 6 * 103 N = 6 kN.

Answer: The net acted on the circus artist with a force of 6 kN.

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