A closed vessel contains 2 liters of oxygen. 1 L of argon was added to the vessel. Calculate the mass

A closed vessel contains 2 liters of oxygen. 1 L of argon was added to the vessel. Calculate the mass fraction of argon in the resulting mixture.

1. Let’s determine the chemical quantities of the presented gases:

n (O2) = V (O2): Vm = 2: 22.4 = 0.0893 mol;

n (Ar) = V (Ar): Vm = 1: 22.4 = 0.0446 mol;

2. Let’s calculate the masses of gases:

m (O2) = n (O2) * M (O2) = 0.0893 * 32 = 2.8576 g;

m (Ar) = n (Ar) * M (Ar) = 0.0446 * 40 = 1.784 g;

3. Find the mass of the mixture:

m (mixture) = m (O2) + m (Ar) = 2.8576 + 1.784 = 4.6416 g;

4. Calculate the mass fraction of argon in the resulting mixture:

w (Ar) = m (Ar): m (mixtures) = 1.784: 4.6416 = 0.3844 or 38.44%.

Answer: 38.44%.