A coil of copper wire with a cross-sectional area of 2 mm / 2 has a mass of 2000 kg. How, without

A coil of copper wire with a cross-sectional area of 2 mm / 2 has a mass of 2000 kg. How, without unwinding a coil, determine the length of the wire S (here something should be gg) = 8.9 * 10 ^ 3 kg / m3

S = 2 mm2 = 2 * 10 ^ -6 m2.

m = 2000 kg.

ρ = 8.9 * 10 ^ 3 kg / m3.

L -?

We represent the mass of a coil of copper wire by the formula: m = ρ * V, where ρ is the density of copper, V is the volume of copper wire.

The volume of copper wire V is expressed by the formula: V = S * L, where S is the cross-sectional area of the wire, L is the length of the wire in the coil.

m = ρ * S * L.

The length of the wire L will be determined by the formula: L = m / ρ * S.

L = 2000 kg / 8.9 * 10 ^ 3 kg / m3 * 2 * 10 ^ -6 m2 = 112359.5 m.

Answer: in a coil L = 112359.5 m of copper wire.