A coil spring with a stiffness of 100 N \ m is suspended by a weight of 1 kg. Determine the period

A coil spring with a stiffness of 100 N \ m is suspended by a weight of 1 kg. Determine the period of oscillation of the weight on the spring.

k = 100 N / m.

m = 1 kg.

g = 9.8 m / s2.

T -?

The period of oscillation of a spring pendulum T is the time of one complete oscillation. The period of a spring pendulum T is determined by the formula: T = 2 * P * √m / √k, where P is the number pi, m is the mass of the load, k is the stiffness of the spring.

T = 2 * 3.14 * √1 kg / √100 N / m = 0.628 s.

Answer: the period of the spring pendulum is T = 0.628 s.



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