A coil with an inductance of 0.13 T is included in an alternating current circuit with a frequency of 300 Hz

A coil with an inductance of 0.13 T is included in an alternating current circuit with a frequency of 300 Hz. How much capacitor needs to be included in this circuit to achieve resonance?

To find the value of the required electrical capacity of the capacitor, we will use the formula: f0 = 1 / (2 * Π * √ (C * L)), whence we express: C = 1 / (4 * Π ^ 2 * f0 ^ 2 * L).

Variables: f0 – current frequency (f0 = 300 Hz); L is the inductance of the switched on coil (L = 0.13 H).

Let’s perform the calculation: C = 1 / (4 * Π ^ 2 * f0 ^ 2 * L) = 1 / (4 * 3.14 ^ 2 * 300 ^ 2 * 0.13) = 2.17 * 10 ^ -6 Ф …

Answer: The capacitance of the connected capacitor must be 2.17 μF.