A color blind man married a color blind woman. Can a healthy son be expected in this marriage?

A color blind man married a color blind woman. Can a healthy son be expected in this marriage? A daughter with color blindness? What is the probability of one or the other event?

As you know, the gene that causes the development of color blindness is inherited in the X – chromosome. Let’s designate a chromosome with a gene that causes color discrimination pathology as X d. The chromosome with the gene for normal color detection is designated X D.
A male with color blindness will have the X d Y genotype and will produce two types of sperm, X d and Y.
A woman who is a carrier of a pathological gene has a heterozygous XDXd genotype. It produces two types of eggs – X D and X d.
The offspring of this married couple will be represented by the following possible options:
healthy girls who are carriers of the pathological gene (X D Xd) -25%;
girls with color blindness (X d Xd) -25%;
healthy boys (X D Y) – 25%;
boys with color blindness (X d Y) -25%.
Answer: the probability of having a healthy son is 25%; The probability of having a daughter with color blindness is 25%.



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