A color image with a size of 30.48 × 30.48 cm is scanned. The resolution of the scanner is 600 × 1200 dpi

| March 10, 2021 | education

A color image with a size of 30.48 × 30.48 cm is scanned. The resolution of the scanner is 600 × 1200 dpi, the color depth is 8 bits. What information volume will the resulting graphic file have?

1) Let’s convert the size of the image from centimeters to inches. Assuming 1 inch = 2.54 cm, we get: 30.48 cm = 30.48 / 2.54 = 12 inches.

2) The size of the image in inches is: 12 * 12 = 144 inches.

3) The information volume of a graphic file is determined by the formula: l = K * i, where k is the total number of image points, i is the color depth.

K = 600 * 1200 * 144 = 103680000 (multiply the scanner resolution by the image size).

l = 103680000 * 8 bits = 829440000 bits.

Let’s translate into megabytes: 829,440,000 bits = 829,440,000 / 8 = 103680000 bytes.

103680000 bytes = 103680000/1024 = 101250 kilobytes.

101250 kilobytes = 101250/1024 = 98.88 megabytes.

Answer: 98.88 megabytes.



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