A concrete slab with a volume of 0.25m3 was raised to a height of 6 meters, the density

A concrete slab with a volume of 0.25m3 was raised to a height of 6 meters, the density of concrete is 2000kg / m3. What work has been done in this case.

Initial data: V (volume of the concrete slab being lifted) = 0.25 m3; h (lifting height of the slab) = 6 m.

Reference data: g (acceleration due to gravity) ≈ 10 m / s2; according to the condition ρb (concrete density) = 2000 kg / m3.

The work that was done to lift the concrete slab is calculated by the formula: A = F * S = ΔEp = m * g * h = ρb * V * g * h.

Calculation: A = 2000 * 0.25 * 10 * 6 = 30,000 J (30 kJ).

Answer: When lifting a concrete slab, work was done at 30 kJ.