A concrete slab with a volume of 0.5m3 was evenly raised to a certain height

A concrete slab with a volume of 0.5m3 was evenly raised to a certain height. What is the height to which the slab was raised, if the work done in this case is 23kJ?

V = 0.5 m3.

ρ = 2300 kg / m3.

g = 10 N / kg.

A = 23 kJ = 23000 J.

h -?

A = m * g * h.

m = ρ * V.

A = ρ * V * g * h.

h = A / ρ * V * g.

h = 23,000 J / 2300 kg / m3 * 0.5 m3 * 10 N / kg = 2 m.

Answer: the concrete slab was raised to a height of h = 2 m.